Set up iterated integrals for both orders of integration. Then evaluate the double integral using the easier order and explain why it's easier. ∬y dA , D is bounded by y = x - 2 , x = y^2 | Numerade

points set up the iterated integral but do not integrate to evaluate the surface integral fds where fr yz2izy and s is the part of the surface isin y that lies above the square si 2 0 y with 45568

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