Q) Find the particular solution of the differential equation dy/dx−y/x+cosec(y/x)=0; given that y=0
2:38
YouTubeShivang Maths Academy
Q) Find the particular solution of the differential equation dy/dx−y/x+cosec(y/x)=0; given that y=0
cbse pyq 2025 dufferential equation Q) Find the particular solution of the differential equation dy/dx−y/x+cosec(y/x)=0; given that y=0, when x=1 #class12 #cbse #maths ##maths #integration #cbse2026 #cbse2026 #differential_equation class12 #maths#differentialequationsclass12 #class #differentialequationsclass12 #cbse2024 #CBSE2025 ,#cbse # ...
8.5K views8 months ago
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Q) Find the particular solution of the differential equation dy/dx−y/x+cosec(y/x)=0; given that y=0
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Q) Find the particular solution of the differential equation dy/dx−y/x+cosec(y/x)=0; given that y=0
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Q) Find the particular solution of the differential equation dy/dx−y/x+cosec(y/x)=0; given that y=0
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Q) Find the particular solution of the differential equation dy/dx−y/x+cosec(y/x)=0; given that y=0
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YouTubeShivang Maths Academy
If y = sinx /√ cosx find dy / dx #cbse2026 #maths #cbse #class12maths
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YouTubeInstructor Alison's Tutorials
Given that y = (sin x)x.xsinx ax, find dydx. | Shaalaa.com
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If y = log.....x 3 find dy/dx #cbse2026 #maths #class12maths #cbse #cbseboard #cbse
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In this video, I explained how to solve an implicit differentiation problem where the equation is given as: If y= root[sin(x y)] and we’re asked to find y′ (dy/dx). Instead of treating y as an independent variable, I showed step by step how to apply implicit differentiation, where both x and y are variables of the function. You’ll learn how to differentiate terms involving y, use the chain rule, and finally make dy/dx the subject of the equation. This method helps you handle tricky calculus prob
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